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malolakrupa
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A certain library assesses fines for overdue books as follows: on the 1st day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount.
What is the total fine for a book on the fourth day it is overdue?
A. $0.60
B. $0.70
C. $0.80
D. $0.90
E. $1.00
I have an issue with the answer to the following problem .
The way I solved it was was
day1 - fine = .10
day 2 - lesser of (.10 + .30 ) OR (0.10*2) = .20 . Hence total fine = .1+.2 = .3
day3 - lesser of (.3 + .3 ) OR (.3*2) . In this case it does not matter which you pick as the result will be 0.6
So the total fine due on day 4 would be 0.6 + 0.3 = 0.9
Could some one clarify ?
What is the total fine for a book on the fourth day it is overdue?
A. $0.60
B. $0.70
C. $0.80
D. $0.90
E. $1.00
I have an issue with the answer to the following problem .
The way I solved it was was
day1 - fine = .10
day 2 - lesser of (.10 + .30 ) OR (0.10*2) = .20 . Hence total fine = .1+.2 = .3
day3 - lesser of (.3 + .3 ) OR (.3*2) . In this case it does not matter which you pick as the result will be 0.6
So the total fine due on day 4 would be 0.6 + 0.3 = 0.9
Could some one clarify ?
