BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Counting Calamity

Expert replies
by tabsang » Sun Dec 16, 2012 4:31 am
How many 4-digit numbers can be formed by using the digits 0-9, so that the numbers contains exactly 3 distinct digits?

(A) 1944
(B) 3240
(C) 3850
(D) 3888
(E) 4216

I got [spoiler](D)[/spoiler] in a little over 3.5 minutes and I don't even know if it's right :O :(
Join the discussion
Source: — Problem Solving |

by puneetkhurana2000 » Sun Dec 16, 2012 2:51 pm
It should be 9*9*8 * 4C2 = 3888.

First 9 for the '000 digit as 0 can't come.
Second 9 for the '00 digit as 0 can come but not the digit that has already been at the '000 place.
Third 8 for the '0 digit. Same logic as above.
4C2 as any of the 3 digits can be repeated but order of digits does matter, so 4*3/2 = 6

Answer D.
Join the discussion

by tabsang » Sun Dec 16, 2012 10:51 pm
Well, here's my approach:

Case I:
The repeated digit is the unit's digit.
So, the 1st, 2nd and 3rd digits can be selected in 9 x 9 x 8 ways, respectively.
Now the 4th digit (unit's digit) can be either equal to the 1st, 2nd or 3rd digit.
Thus, in all we have:
9x9x8x3

Case II:
The repeated digit is the ten's digit.
So, the 1st, 2nd and 4th digits can be selected in 9 x 9 x 8 ways, respectively.
Now the 3rd digit (ten's digit) can be either equal to the 1st or 2nd digit.
Thus, in all we have:
9x9x2x8

Case III:
The repeated digit is the hundred's digit.
So, the 1st, 3rd and 4th digits can be selected in 9 x 9 x 8 ways, respectively.
Now the 2nd digit (hundred's digit) is equal to the 1st digit.
Thus, in all we have:
9x1x9x8

In totality, we have 9x9x8(3+2+1) = 9x9x8x6 = [spoiler](D) 3888[/spoiler]
Join the discussion

by tabsang » Sun Dec 16, 2012 10:59 pm
puneetkhurana2000 wrote:It should be 9*9*8 * 4C2 = 3888.

First 9 for the '000 digit as 0 can't come.
Second 9 for the '00 digit as 0 can come but not the digit that has already been at the '000 place.
Third 8 for the '0 digit. Same logic as above.
4C2 as any of the 3 digits can be repeated but order of digits does matter, so 4*3/2 = 6

Answer D.
Hey Puneet,

Could you explain the last part of your solution in more detail?
I didn't follow it.
If you say that the order of digits matters then use of permutations is in order right?
But you've used combinations (4C2).
Moreover, you've used 4C2... i.e (4 options for two slots????).
Now, we only have one slot and that can be filled by a digit that is same as one of the other 3 digits in the number, right?? And then we get an arrangement with exactly 3 distinct digits.

TIA :)
Join the discussion

by GMATGuruNY » Mon Dec 17, 2012 4:27 am
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by tabsang » Mon Dec 17, 2012 6:50 am
GMATGuruNY wrote:Check my 3 posts here:

https://www.beatthegmat.com/nice-countin ... 91869.html
Thanks Mitch.
That was really helpful, as always :)

Cheers,
Taz
Join the discussion