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dddanny2006
- Master | Next Rank: 500 Posts
- Posts: 209
- Joined: Thu Jan 12, 2012 12:59 pm
A tank is fitted with an inlet which takes 1 hour to completely fill the empty tank. The tap was turned on when the tank was empty. When the tank was half filled , it developed a leak and as a result it took totally 65 minutes to fill the tank. As soon as the tank got filled completely, the tap was turned off but the leakage continued. How long will it take for the leakage to empty the tank completely.
Answer is 7hrs
According to me-
Rate is 1tank/hr
Rate of leak is x tank/hr
Due to the leak it has taken 65minutes to fill the tank.Since the leaking spot is in the middle of the tank,its safe to say that it has taken (65-30)=35minutes to fill the top half of the tank
So we can formulate an equation like this one below:
(1-x)*35=(1/2)
35-35x=1/2
34.5=35x => x=(34.5/35)
Now we have the rate of leakage equaling (34.5/35)
Now (34.5/35) * Time =0.5(Because only half the tank could possibly leak) Therefore
Time=(35/69)hrs==========This answer is wrong
However if Ive made a mistake of considering the leak to be happening just at the half of the tank,
the main equation can be reformulated as
(1-x)*65=1
65-65x=1
x=64/65
(64/65)*Time = 1
Time =65/64 hrs======This too is a wrong answer
Please tell me where my understanding is misleading me even though there might be a totally different approach to this problem.
The above method I used was influenced to an extent by this problem below
Two inlet taps can fill a tank in 12 hours and 15 hours respectively. There is an out let tap at the middle of the tank which can empty the full tank in 60 hours. If all the taps are opened together, after how much time, the tank will be full?
1) 7 hrs 5 mins 2) 7 hrs 30 mins 3) 9 hrs 12 mins 4) 12 hrs
Thanks
Dan
Answer is 7hrs
According to me-
Rate is 1tank/hr
Rate of leak is x tank/hr
Due to the leak it has taken 65minutes to fill the tank.Since the leaking spot is in the middle of the tank,its safe to say that it has taken (65-30)=35minutes to fill the top half of the tank
So we can formulate an equation like this one below:
(1-x)*35=(1/2)
35-35x=1/2
34.5=35x => x=(34.5/35)
Now we have the rate of leakage equaling (34.5/35)
Now (34.5/35) * Time =0.5(Because only half the tank could possibly leak) Therefore
Time=(35/69)hrs==========This answer is wrong
However if Ive made a mistake of considering the leak to be happening just at the half of the tank,
the main equation can be reformulated as
(1-x)*65=1
65-65x=1
x=64/65
(64/65)*Time = 1
Time =65/64 hrs======This too is a wrong answer
Please tell me where my understanding is misleading me even though there might be a totally different approach to this problem.
The above method I used was influenced to an extent by this problem below
Two inlet taps can fill a tank in 12 hours and 15 hours respectively. There is an out let tap at the middle of the tank which can empty the full tank in 60 hours. If all the taps are opened together, after how much time, the tank will be full?
1) 7 hrs 5 mins 2) 7 hrs 30 mins 3) 9 hrs 12 mins 4) 12 hrs
Thanks
Dan














