sud21 wrote:If three people are to be selected from eight people, who include Bob and Nancy, how many ways are possible that Bob, not Nancy is selected?

First select Bob (since he MUST be part of the 3-person selection).
This leaves 7 people, and Nancy is one of them.
We need to choose 2 more people from the remaining 7 people such that Nancy is not one of them.
So . . . ask Nancy to leave the room (this guarantees that she is not selected)

In how many ways can we select 2 people from 6 people (none of whom is Nancy)?
We can accomplish this in 6C2 (15) ways.

The answer is 15

Cheers,
Brent