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Question of the Day - 4th August, 2009 - Bonus Question

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by quant-master » Tue Aug 04, 2009 12:52 pm
The Question:

Mixture A is 15 percent alcohol, and mixture B is 50 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 30 percent alcohol, approximately how many gallons of mixture A are in the mixture?

1.5

1.7

2.3

2.5

3.0

OA with explanation will be posted in my blog in 24 hrs time.

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https://gmat-quants.blocked - My Blog Updated almost daily with new quant fundas. Find collection of quants question in my blog
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by truplayer256 » Tue Aug 04, 2009 1:59 pm
Mixture A contains x gallons.

Mixture B contains y gallons.

Amount of alcohol in Mixture A= .15(x)

Amount of alcohol in Mixture B=.5(x)

x+y=4

.15(x)+.5(y)=1.2

y=4-x

.15(x)+.5(4-x)=1.2

.15(x)+2-.5(x)=1.2

2-.35x=1.2

-.8=-.35x

x~2.3 gallons C.
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by umaa » Wed Aug 05, 2009 7:08 am
I agree with truplayer256. The answer should be C.
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by quant-master » Wed Aug 05, 2009 10:11 am
umaa wrote:I agree with truplayer256. The answer should be C.
thats correct. OA is C. Detailed explanation is posted in my blog

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