- Jinglander
- Senior | Next Rank: 100 Posts
- Posts: 58
- Joined: Thu Jul 22, 2010 5:40 pm
- Thanked: 1 times
9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?
I know how to solve this multiply the prob of coosing 6 from 3 and 2 from 3 but how about solving it with using 9! as the denominator.
I know how to solve this multiply the prob of coosing 6 from 3 and 2 from 3 but how about solving it with using 9! as the denominator.

















