When you post a problem, please include the answer choices.
Here, the answer choices are as follows:
36
36√3
24√3 + 24
24√3 + 36
72
CD + CE + FG = 12+12+12 = 36.
∆ADG:
On the GMAT, the perimeter of a 30-60-90 triangle will ALWAYS include √3.
Implication:
Since DG = 12, AD + AG = (something with √3).
∆BEF:
Since ∆BEF and ∆ADG are congruent, BE + BF = AD + AG = (something with √3).
Thus:
∆ABC = 36 + 2(something with √3).
Only
D is viable.
The correct answer is
D.
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