BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

1000PS Section 3 Qusetion 20

Expert replies
by cindyqtran » Sat Sep 22, 2007 10:06 pm
picture is attached.
20. If each side of ΔACD above has length 3 and if AB has length 1, what is the area of region BCDE?
(A) 9/4
(B) 7/4*sqrt(3)
(C) 9/4*sqrt(3)
(D) 7/2*sqrt(3)
(E) 6 +sqrt(3)

thanks!![/quote]
Attachments
untitled.JPG
Join the discussion
Source: — Problem Solving |

by kajcha » Sun Sep 23, 2007 2:45 pm
Triangle ACD is equilateral triangle. So, each angle is 60 degrees

AB = 1. tan 60 = root(3) = BE/AB => BE = root(3)

Area of traingle ABE = AB*BE/2 = root(3)/2 ----(1)

Area of trianle ACD = root(3)*3*3/2 ----(2)

Area of region BCDE = (2)-(1) = 7*root(3)/4
Join the discussion

by cindyqtran » Sun Sep 23, 2007 3:44 pm
thanks. forgot about 30-60-90 triangles/
Join the discussion