Difficult Math Problem #71 - Combinations
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- aim-wsc
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4 to the power of 5
answer: 4^5
I want you to provide the explanation to the answer if you have.
you know i suck at giving proper explanantion.
answer: 4^5
I want you to provide the explanation to the answer if you have.
you know i suck at giving proper explanantion.
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OA:
5 rings, 4 fingers
1st ring can be worn on any of the 4 fingers => 4 possibilities
2nd ring can be worn on any of the 4 fingers => 4 possibilities
3rd ring can be worn on any of the 4 fingers => 4 possibilities
4th ring can be worn on any of the 4 fingers => 4 possibilities
5th ring can be worn on any of the 4 fingers => 4 possibilities
Total possibilities = 4*4*4*4*4 = 4^5.
5 rings, 4 fingers
1st ring can be worn on any of the 4 fingers => 4 possibilities
2nd ring can be worn on any of the 4 fingers => 4 possibilities
3rd ring can be worn on any of the 4 fingers => 4 possibilities
4th ring can be worn on any of the 4 fingers => 4 possibilities
5th ring can be worn on any of the 4 fingers => 4 possibilities
Total possibilities = 4*4*4*4*4 = 4^5.