since x is an integer and increases
2x-5 will increase
1/x will decrease and hence 1-1/x increase
x(x-1) increase..hence 1/(x^2-x) decrease
so ans C
Arithmetic Prob
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- thephoenix
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1) 2x-5 as x increases from 2x will inc for the given condition and therefore the value for 2x-5 will also inc
2) for the given condition 1/x decreases wrt to increasing value of x and therefore the value for 1-1/x will also inc
3)1/x(x-1) x(x-1) increases and the corresponding value of the exp dec
so only 1 and 2 are increasing C
2) for the given condition 1/x decreases wrt to increasing value of x and therefore the value for 1-1/x will also inc
3)1/x(x-1) x(x-1) increases and the corresponding value of the exp dec
so only 1 and 2 are increasing C
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frank1
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Time 1:51
IMO C
I think what is being test here is
people might start with x=165 and 166 and all(trap)
which will take lot of time...
rather than that...
if we do x=1...2...3
then it will be possible to solve it,with in 2 minutes....
IMO C
I think what is being test here is
people might start with x=165 and 166 and all(trap)
which will take lot of time...
rather than that...
if we do x=1...2...3
then it will be possible to solve it,with in 2 minutes....
- Patrick_GMATFix
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@Selango,
Yes, you can plug in positive integers greater than 1. Generally when a question asks you how certain numbers behave, you can plug in other numbers that have similar behaviors. Along the number line, numbers can be divided into the following groups: {-infinity to -1} {-1 to 0} {0 to 1} and {1 to +infinity}
Instead of dealing with decimals between 165 and 166, you could deal with 2 or 3.
PS. The technique above wouldn't apply if the question is about even/odd of course, since that property divides numbers into different groupings.
This is OG12 # 176. A couple of ways to solve are attached.
-Patrick
Yes, you can plug in positive integers greater than 1. Generally when a question asks you how certain numbers behave, you can plug in other numbers that have similar behaviors. Along the number line, numbers can be divided into the following groups: {-infinity to -1} {-1 to 0} {0 to 1} and {1 to +infinity}
Instead of dealing with decimals between 165 and 166, you could deal with 2 or 3.
PS. The technique above wouldn't apply if the question is about even/odd of course, since that property divides numbers into different groupings.
This is OG12 # 176. A couple of ways to solve are attached.
-Patrick
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- OG12-PS176.pdf
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