BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

How many positive integers less than 10,000

Expert replies
by sachin_yadav » Tue Jan 05, 2016 1:27 pm
How many positive integers less than 10,000 are such that the product of their digits is 30?

A. 12
B. 24
C. 36
D. 38
E. 50

OA is E

Please share your approach
Never surrender
Join the discussion
Source: — Problem Solving |

by DavidG@VeritasPrep » Tue Jan 05, 2016 1:46 pm
sachin_yadav wrote:How many positive integers less than 10,000 are such that the product of their digits is 30?

A. 12
B. 24
C. 36
D. 38
E. 50

OA is E

Please share your approach
First, let's lay out the ways we can multiply several positive digits (numbers between 1 and 9) to get 30. (Because the number must be less than 10,000, we know that we want fewer than five digits.)

6 * 5 * 1 will work --> There are 6 ways we can arrange these 3 digits. (Any of the 3 numbers can be in the hundreds place. Any of the 2 remaining numbers can be in the tens place. And the remaining number must be in the units place: 3*2*1 = 6)

3*2*1*5 will work --> There are 24 ways we can arrange these 4 digits: 4*3*2*1 = 24

6*5*1*1 will work ---> There are 12 ways we can arrange these 4 digits. (If all 4 digits are different, there are 24 arrangements. But swapping the 1's will not result in unique numbers, so we need to divide by two to account for the fact that the two 1's are interchangeable.)

6*5 will work ---> 2 ways to arrange these 2 digits

2*3*5 will work ---> 6 ways (3*2*1) to arrange there 3 digits

Now add up the numbers in red: 6 + 24 + 12 + 2 + 6 = 50
Veritas Prep | GMAT Instructor

Veritas Prep Reviews
Save $100 off any live Veritas Prep GMAT Course
Join the discussion

by Brent@GMATPrepNow » Tue Jan 05, 2016 2:48 pm
Here's a similar question to practice with: https://www.beatthegmat.com/positive-int ... 83442.html

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by Matt@VeritasPrep » Fri Jan 08, 2016 12:59 pm
Casework (as David showed) is probably the best way; this is an approach that is very common for GMAT-level combinatorics questions.
Join the discussion