hi, here there are different approaches I think
One option is to resolve the sq
is 20 the answer?
(a +b)^2 = a^2 + 2ab +b^2
So you get 9 + 9 + 2(a+b)(a-b)
and the last term is equal to a^2 - b^2 = 81-80
18 + 2 = 20
maybe I can write down with formulas if it is not clear
exponents - one more
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OA is 20 !moliver wrote:hi, here there are different approaches I think
One option is to resolve the sq
is 20 the answer?
(a +b)^2 = a^2 + 2ab +b^2
So you get 9 + 9 + 2(a+b)(a-b)
and the last term is equal to a^2 - b^2 = 81-80
18 + 2 = 20
maybe I can write down with formulas if it is not clear
I am sorry I didn't quite get your explanation. What is the formula for solving such equations?
From your explanation:
I am aware abt this one:(a +b)^2 = a^2 + 2ab +b^2
so in our case ... what is a and what is b here ?
Please let me know. Thanks !!
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moliver
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Sorry gmatguy81, I didn't want to write down all.
a= (9 +80^(1/2))^(1/2)
b= (9 -80^(1/2))^(1/2)
we eliminate the root for the terms a^2 and b^2 and we have the other term that is: 2ab =
(9 +80^(1/2))^(1/2) * (9 -80^(1/2))^(1/2)
we can multiple what is inside of the root and make a big root
and what is inside of the root has the form of: (a+b)(a-b) with is equal to a^2 - b^2 so
{(9 +80^(1/2)) * (9 -80^(1/2))}^(1/2)
= (9*9-80)^(1/2)
so putting all together, we have 9+9+2*1= 20
I hope this make more sense.
Please let me know if you need further explanation, I would be glad to help you.
a= (9 +80^(1/2))^(1/2)
b= (9 -80^(1/2))^(1/2)
we eliminate the root for the terms a^2 and b^2 and we have the other term that is: 2ab =
(9 +80^(1/2))^(1/2) * (9 -80^(1/2))^(1/2)
we can multiple what is inside of the root and make a big root
and what is inside of the root has the form of: (a+b)(a-b) with is equal to a^2 - b^2 so
{(9 +80^(1/2)) * (9 -80^(1/2))}^(1/2)
= (9*9-80)^(1/2)
so putting all together, we have 9+9+2*1= 20
I hope this make more sense.
Please let me know if you need further explanation, I would be glad to help you.
