A set of 13 different integers has a median of 30 and a range of 30. What is the greatest possible integer that could be in this set?
A)36
B)43
C)54
D)57
E)60
A)36
B)43
C)54
D)57
E)60
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In such a case there should be changes in papgust's 300 question set...selango wrote:Median =30
High-Low=30
Low<=30
High=30+Low
-->High<=60
Highest possible integer is 60
Pick E
hi, thank you for your post but the thing i dont understand is why do we have to fnd the highest number of x1? why its not the smallest?life is a test wrote:IMO C
median of 13 nums = 30; this means that the 7th value = 30. range of 30 and be denoted by x13-x1 = 30 (where x13 is the 13th term and x1 is first term).
to get the largest value of x13 we have to try and get the largest value of x1 and still preserve the condition of the difference being 30 and all the nums being different.
counting back from the median of 30, x1 can be 24 (remember we are looking for the highest value of x1).
x13 -x1 = 30 -> x13-24 = 30 -> x13 = 54.
to get the greatest num, we have to try and make the remaining 12 nums as small as possible bearing in mind that eachnumhas to be different.
hope that helps
This question asks for the greatest possible integer.diebeatsthegmat wrote:hi, thank you for your post but the thing i dont understand is why do we have to fnd the highest number of x1? why its not the smallest?life is a test wrote:IMO C
median of 13 nums = 30; this means that the 7th value = 30. range of 30 and be denoted by x13-x1 = 30 (where x13 is the 13th term and x1 is first term).
to get the largest value of x13 we have to try and get the largest value of x1 and still preserve the condition of the difference being 30 and all the nums being different.
counting back from the median of 30, x1 can be 24 (remember we are looking for the highest value of x1).
x13 -x1 = 30 -> x13-24 = 30 -> x13 = 54.
to get the greatest num, we have to try and make the remaining 12 nums as small as possible bearing in mind that eachnumhas to be different.
hope that helps
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