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by sacx » Tue Apr 28, 2009 5:11 am
√[2√63 + 2/(8+3√7)]

= √[6√7 + 2/(8+3√7)]
= √2[3√7 + 1/(8+3√7)]
= √2[(24√7+63 + 1)/(8+3√7)]
=√2[(24√7+64)/(8+3√7)]
=√16[(3√7+8)/(8+3√7)]
= 4
SACX
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