BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Exponents

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Site Admin
Posts: 2567
Joined: Thu Jan 01, 2009 10:05 amFollowed by: 550 members
Thanked: 712 times
GMAT Score:770

by DanaJ » Thu Jan 29, 2009 10:40 am
(5^21) * (4^11 )= (5^21) *[(2^2)^11] = (5^21) * (2^22) = [(5*2)^21] * 2 = (10^21)*2, so n = 21.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 27
Joined: Thu Jan 29, 2009 9:57 am
Thanked: 1 times

by masuarezdl » Thu Jan 29, 2009 10:58 am
DanaJ wrote:(5^21) * (4^11 )= (5^21) *[(2^2)^11] = (5^21) * (2^22) = [(5*2)^21] * 2 = (10^21)*2, so n = 21.
There we go! Thanks Dana.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 110
Joined: Sun May 25, 2008 3:45 pm

by ajmoney09 » Thu Jan 29, 2009 8:28 pm
The exponents have to be equal to multiple the base terms?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Site Admin
Posts: 2567
Joined: Thu Jan 01, 2009 10:05 amFollowed by: 550 members
Thanked: 712 times
GMAT Score:770

by DanaJ » Thu Jan 29, 2009 10:44 pm
Yes, they sure do. Say you have (5^6)*(2^8). This is equal to (5^6)*(2^6)*(2^2) = (5*2)^6 *(2^2) = (10^6)*4. As you can see, we have 2^2 "on the side".
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 117
Joined: Fri Oct 17, 2008 7:41 am

by awilhelm » Fri Jan 30, 2009 7:52 am
My slightly slower approach:

5^21 * 4^11 = 2 * 10^n
5^21 * 2^22 = 2^1 * 2^n * 5^n
5^21 * 2^22 = 5^n * 2^n+1

From here you can see that n = 21
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 132
Joined: Tue Oct 07, 2008 4:59 pm
Thanked: 4 times

The exponents

by vladmire » Fri Jan 30, 2009 8:59 am
ajmoney09 wrote:The exponents have to be equal to multiple the base terms?[/quote

I'm getting lost right here
(5^21) * (2^22) = [(5*2)^21] * 2
How is [(5*2)^21]*2 equal to (5^21) * (2^22)

The exponents aren't equal are they how can i multiply the base terms
Last edited by vladmire on Fri Jan 30, 2009 9:02 am, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Community Manager
Posts: 1049
Joined: Sun Apr 06, 2008 5:15 pmFollowed by: 27 members
Location: Pittsburgh, PA
Thanked: 113 times
GMAT Score:710

Re: The exponents

by dmateer25 » Fri Jan 30, 2009 9:02 am
vladmire wrote:
ajmoney09 wrote:The exponents have to be equal to multiple the base terms?[/quote

I'm getting lost right here
(5^21) * (2^22) = [(5*2)^21] * 2
How is [(5*2)^21]*2 equal to (5^21) * (2^22)
Maybe this will help:

[(5*2)^21]*2 = 5^21 * 2^21 *2 = 5^21 * 2^22
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1