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Letters (probability)

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Source: — Problem Solving |

by LSB » Mon Sep 01, 2008 1:01 pm
the attachments in this post are quite large. I am reattaching as word documents.
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by parallel_chase » Mon Sep 01, 2008 1:17 pm
The probability of A letter going to A envelop and B, C, and D in wrong

A going into right envelop is 1/4
B going into wrong envelop is 2/3 ( 1-1/3)
C going into wrong envelop is 1/2
D automatically will go into the wrong envelop 1

1/4*2/3*1/2*1 = 1/12 (multiplication because everything occurs at once)

Similarly the same procedure will follow for B, C & D and the result will also be the same

1/12+1/12+1/12+1/12 = 4/12 = 1/3.
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by 4meonly » Wed Sep 03, 2008 7:25 am
Anybody, please find the flaw in my reasosning:

1. To make 1st letter with correct adress:
1/4*2/3*1/2*1 = 1/12

2. To make 2nd letter with correct adress:
3/4*1/3*1/2*1 = 1/8

3. To make 3rd letter with correct adress:
3/4*2/3*1/2*1 = 1/4

4. To make 4th letter with correct adress:
3/4*2/3*1/2*1 = 1/4

summ will be 17/24
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by canuckclint » Wed Sep 03, 2008 4:15 pm
4meonly wrote:Anybody, please find the flaw in my reasosning:

1. To make 1st letter with correct adress:
1/4*2/3*1/2*1 = 1/12

2. To make 2nd letter with correct adress:
3/4*1/3*1/2*1 = 1/8

3. To make 3rd letter with correct adress:
3/4*2/3*1/2*1 = 1/4

4. To make 4th letter with correct adress:
3/4*2/3*1/2*1 = 1/4

summ will be 17/24
The flaw is in 1 and multiplications in general
1 should be = 2/24
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by 4meonly » Thu Sep 04, 2008 8:00 am
1 should be = 2/24

does not this mean that 2/24 = 1/12 ?
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