BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 21
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

Sep 21 to Oct 9, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Two issues...

Expert replies
by mixpanda » Sat May 02, 2009 11:22 am
Issue 1:

5^k - 5^(k-1) = 5^k - (1/5)5^k

Is this true because regardless of the value of k, a negative one in the power means that it is at least divided by 5 once?

So would 5^(k+1) = 25^k ?

Issue 2:

ax^2 + bx = c = 0

When we use the quadratic formula to find x, we end up with two roots, right? Are there any instances where you just know beforehand that there is only one root?
Join the discussion
Source: — Problem Solving |

by DanaJ » Sat May 02, 2009 11:28 pm
1. Indeed, 5^k - 5^(k-1) = 5^k - (1/5)*(5^k). What you're actually doing here is spotting a common factor, which is 5^k. You can easily factorize it now, since it will be obvious that:

5^k - (1/5)*(5^k) = (5^k)*(1 - 1/5) = (5^k)*4/5

BUT

you made a mistake here:

5^(k+1) = 25^k

5^(k+1) = 5*(5^k) - as you can see, this is very different from 25^k. Just consider k = 3: 5^(k+1) = 5^4 = 625 = 5*125 = 5*5^3. HOWEVER, 25^4 is actually 625*625, since 25^2 = 625.


2. It's actually the easiest thing to know that the equation has only one root. This only happens when you can make a perfect square out of it, in other words when it follows the pattern on the formula:

(x + n)^2 = x^2 + 2xn + n^2.

Let me give you a few examples:
x^2 + 4x + 4 = x^2 + 2*2*x + 2^2 = (x + 2)^2 - the only root will be -2

x^2 + 10x + 25 = (x + 5)^2 - the only root will be -5

x^2 - 6x + 9 = (x - 3)^2 - the only root will be 3

x^2 - 4x + 3 - we can't find a square here, because x^2 - 4x + 3 = (x - 1)(x - 3) - as you can see, the equation has two roots, 1 and 3.
Join the discussion