This is a PS question from Manhattan Cat 3:
If x and y are integers and
(15x + 15x+1) / 4y = 15y,
what is the value of x?
Their solution
(15x + 15x+1) = 15y4y
[15x + 15x(15^1)] = 15y4y
(15x )(1 + 15) = 15y4y
(15x)(16) = 15y4y
(3x)(5x)(24) = (3y)(5y)(22y)
Since both sides of the equation are broken down to the product of prime bases, the respective exponents of like bases must be equal.
2y = 4 so y = 2.
x = y so x = 2.
My question
I might be very stupid now. I understand all the complex parts (prime bases), but how did they go from here [15x + 15x(15^1)] = 15y4y to here (15x )(1 + 15) = 15y4y
Thanks alot
If x and y are integers and
(15x + 15x+1) / 4y = 15y,
what is the value of x?
Their solution
(15x + 15x+1) = 15y4y
[15x + 15x(15^1)] = 15y4y
(15x )(1 + 15) = 15y4y
(15x)(16) = 15y4y
(3x)(5x)(24) = (3y)(5y)(22y)
Since both sides of the equation are broken down to the product of prime bases, the respective exponents of like bases must be equal.
2y = 4 so y = 2.
x = y so x = 2.
My question
I might be very stupid now. I understand all the complex parts (prime bases), but how did they go from here [15x + 15x(15^1)] = 15y4y to here (15x )(1 + 15) = 15y4y
Thanks alot












