AshB wrote:A list contains 3 different numbers. Does the median of the 3 numbers equal the average(arithmetic mean) of the 3 numbers?
1) The range of 3 numbers is equal to twice the difference between the greatest number and the median
2) The sum of the 3 numbers is equal to 3 times one of the numbers
When numbers are EVENLY SPACED, the median is equal to the average.
Question stem, rephrased:
Are the 3 numbers evenly spaced?
Statement 1:
Let the 3 numbers, in ascending order, be a, b and c.
Range = biggest - smallest = c-a.
Difference between the greatest number and the median = c-b.
Since the range is equal to twice the difference between the greatest number and the median, we get:
c-a = 2(c-b)
c-a = 2c - 2b
2b = a + c
b = (a+c)/2.
Since b is equal to the average of a and c, b must be HALFWAY between a and c, implying that a, b and c are EVENLY SPACED.
SUFFICIENT.
Statement 2:
Case 1: One of the numbers is 1.
If the sum is equal to three times 1, then the sum is equal to 3.
Options for the 3 numbers:
0, 1, 2 --> 0+1+2 = 3.
-1, 1, 3 --> -1+1+3 = 3
-10, 1, 12 --> -10+1+12 = 3.
In every case, the 3 numbers are EVENLY SPACED.
Case 2: One of the numbers is 10.
If the sum is equal to three times 10, then the sum is equal to 30.
Options for the 3 numbers:
9, 10, 11 --> 9+10+11 = 30.
0, 10, 20 --> 0+10+20 = 30.
-10, 10, 30 --> -10+10+30 = 30.
In every case, the 3 numbers are EVENLY SPACED.
As Cases 1 and 2 illustrate, for the sum to be equal to three times one of the numbers, the 3 numbers must be EVENLY SPACED.
SUFFICIENT.
The correct answer is
D.
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