A certain play performance....

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A certain play performance....

by romeroil » Mon Dec 07, 2009 1:15 am
For a certain play peformance, adults' tickets were sold for $12 each and children's tickets were sold for $8 each. How many children's tickets were sold for the performance?

(1) The total revenue from the sale of adults' and children's tickets for the performance was $5,040.
(2) The number of adults' tickets sold for the performance was 1/3 the total number of adults' and children's tickets sold for the performance.

I know each statement alone is not sufficient, but when I try to set up the equation using both statements, I cannot solve for one variable.

Please help.
Source: — Data Sufficiency |

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by papgust » Mon Dec 07, 2009 1:52 am
IMO it can be solved using both statements.

Assume x as no. of adults ticket and y as no. of children ticket

From i, we get 12x + 8y = 5040....... (1)

From ii, we get x = 1/3 * (x+y)

x = x/3 + y/3

x - x/3 = y/3

2x/3 = y/3

2x - y = 0 ........ (2)

Using 1 and 2, we can find out number of children's tickets.

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by romeroil » Mon Dec 07, 2009 4:40 am
Yup...see it now. Thanks!