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by maolivie » Mon Jul 09, 2007 12:43 pm
A five-member committee is to be formed from a group of five military officers and nine civilians. If the committee must include at least two officers and two civilians, in how many different ways can the committee be chosen?

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by givemeanid » Mon Jul 09, 2007 3:35 pm
The committe can be
1. 3 officers 2 civilians OR
2. 2 officers 3 civilians

Total number of ways to choose 1 = 5C3 * 9C2 = 10 * 36 = 360
Total number of ways to choose 2 = 5C2 * 9C3 = 10 * 84 = 840

So, altogether, total number of ways = 360+840 = 1200
So It Goes
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