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Equation Problem ...

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Equation Problem ...

by camitava » Thu Sep 13, 2007 4:29 am
Guys I have faced the following problem but according to me, the answer should be 1.62. But no such option is here.

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5. At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost? 
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90
Refer my approach -
H + C = 3.59
H + F = 4.40
and F = 2C
So C = .81
and F = 1.62

Guys pls tell me where I am wrong? Pls help me out ...
Correct me If I am wrong


Regards,

Amitava
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by Bharat » Thu Sep 13, 2007 11:48 pm
Let me know if the correct answer is E.

Your answer is correct, however there seems to be a type in the question; Hamburger + coleslaw cost should be $3.95 which will solve the value of french fries to be $0.90.

FYI, the same questions was discussed in either this or some other similar forum before the typo was figured out : )
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by camitava » Fri Sep 14, 2007 12:16 am
If it has already been discussed here, then sorry its my fault. I should find the forum then! However Bharat thanks once again (Total count of thanks become four now! - Ha ha ha!).
Correct me If I am wrong


Regards,

Amitava
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by Bharat » Thu Sep 20, 2007 12:08 am
Amitava, you are welcome!!!
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