BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Ratio Problem OG 192

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 165
Joined: Wed Mar 24, 2010 8:02 am
Thanked: 2 times
Followed by:1 members

Ratio Problem OG 192

by HPengineer » Mon Aug 09, 2010 8:03 pm
The ratio, by volume, of soap to alcohol to water in a certain solution is 2:50:100. The solution will be altered so that the ratio of soap to alcohol is doubled while the ratio of soap to water is halved. If the altered solution will contain 100 cubic centimeters of alcohol how many cubic centimeters of ware will it contain?

A.) 50
B.) 200
C.) 400
D.) 624
E.)800

Anyone have an cool tricks for this problem? its really bugging me...
Top
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 161
Joined: Mon Apr 05, 2010 9:06 am
Location: Mumbai
Thanked: 37 times

by 4GMAT_Mumbai » Mon Aug 09, 2010 8:47 pm
Hi,

S:A:W = 1:25:50

Ratio of soap to alcohol is doubled. Current ratio = 1:25.

Double it and you get 2:25.

So, add 1 part soap to this solution and the overall ratio becomes 2:25:50.

Ratio of soap to water is halved. Original ratio = 1:50.

Halve it and you get 1:100; which is equivalent to 2:200.

Add 150 parts of water to the previous solution and the new ratio becomes 2:25:200

S:A:W = 2:25:200 which is equivalent to 8:100:800.

Why are we doing this? Because the question says that there are 100 cc of alcohol.

Hence, it has 800 cc of water in it.

Hope this helps. Thanks.
Naveenan Ramachandran
4GMAT, Dadar(W) & Ghatkopar(W), Mumbai
Top
Master | Next Rank: 500 Posts
Posts: 165
Joined: Wed Mar 24, 2010 8:02 am
Thanked: 2 times
Followed by:1 members

by HPengineer » Wed Aug 11, 2010 8:42 am
yup now i got this problem... hopefully no problem like this will never give me trouble again Thanks for the help
Top
User avatar
Legendary Member
Posts: 1460
Joined: Tue Dec 29, 2009 1:28 am
Thanked: 135 times
Followed by:7 members

by selango » Wed Aug 11, 2010 8:47 am
S:A:W=2:50:100

Altered Solution:

S:A=4:50 or A:S=25:2

S:W=1:100 or S:W=2:200

A:S:W=25:2:200 or S:A:W=2:25:200

A:W=25:100 or A:W=100:800

Pick E
--Anand--
Top
Post new topic Post Reply
• Page 1 of 1