If x, y, and k are positive numbers such that (X/(x+y) )(10) + (y/(x+y) )(20) = k and if x < y, which of the following could be the value of k?
A. 10
B. 12
C. 15
D. 18
E. 30
A. 10
B. 12
C. 15
D. 18
E. 30
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Ian,Ian Stewart wrote:(x/(x+y) )(10) + (y/(x+y) )(20) = k
is just the equation for a weighted average. It's exactly the equation you would write down if you were asked the following question:
At Company A, the x men employees make an average of $10/hour. The y women employees make an average of $20/hour. What is the average wage of all employees at Company A?
If y > x, the answer could be anything between 15 and 20. D.
Yes, that's exactly right- because 15 is halfway between 10 and 20, if you have more men, the average wage will be between 10 and 15, and if you have more women, the average wage will be between 15 and 20.ildude02 wrote:How did you certainly conclude that it should be between 15 and 20. I can see that the average wage should be closer towards the Y's wage since y is greater then x, but not sure how we could say that it should be inbetween 15 and 20. Is it just because, if we have choose 14, it will be closer to X's wage then Y and that would mean , X is more than Y?
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