BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Right triangle inscribed in a circle

Expert replies
by sk8ternite » Mon Aug 24, 2009 7:49 pm
What is the greatest possible area of a triangular region with one vertex at the center of a circle of radius 1 and the other two vertices on the circle?

A) sqr(3)/4
B) 1/2
C) (pie)/4
D) 1
E) sqr(2)


This problem has been posted before, but I had a question regarding the fundamentals behind it. In order to maximize the area of a triangle, you set the two sides perpendicular to each other and make a 90 degree angle. But I thought a right triangle inscribed in a circle had to have a diameter as one of its sides? If you make two radiuses perpendicular to each other, can it be a right triangle?
Join the discussion
Source: — Problem Solving |

by fltingley » Tue Aug 25, 2009 7:51 am
I think your confusion lies in this statement:

"But I thought a right triangle inscribed in a circle had to have a diameter as one of its sides?"

Conceptualize just that that for a moment: imagine a circle with a line running the diameter. This means you have essentially cut the circle in half since the diameter has to run through the center of the circle.

Now, with one line running border-to-border through the circle, where does the right angle vertices go? Answer: it can't go anywhere since the two ends of your line are touching the edges of the circle. Any movement to try and create a right angle at either edge of the line will result in that perpendicular line running OUTSIDE of the circle.

Make sense?
Join the discussion

by sk8ternite » Tue Aug 25, 2009 7:59 am
fltingley wrote:I think your confusion lies in this statement:

"But I thought a right triangle inscribed in a circle had to have a diameter as one of its sides?"

Conceptualize just that that for a moment: imagine a circle with a line running the diameter. This means you have essentially cut the circle in half since the diameter has to run through the center of the circle.

Now, with one line running border-to-border through the circle, where does the right angle vertices go? Answer: it can't go anywhere since the two ends of your line are touching the edges of the circle. Any movement to try and create a right angle at either edge of the line will result in that perpendicular line running OUTSIDE of the circle.

Make sense?
Ok, I was thinking that the only right angle that could exist in a circle was one that had a diameter as one of its sides. But I guess other types of 90 degree angles can exist within a circle. Is this correct?
Join the discussion