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DS with modulus

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Source: — Data Sufficiency |

by tohellandback » Wed Aug 19, 2009 8:42 pm
IMO D

1)2^|x|= 2^x
so |x|=x
so x>=0
SUFF

2)3^|x|<=3^x
i think 3^|x| can never be < 3^x
because minimum value of 3^|x| is 1 when x=0
for any other value 3^|x|>=3^x
so here only the equality holds true
3^|x|=3^x
this is same as statement 1.
SUFF
The powers of two are bloody impolite!!
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by adilka » Wed Aug 19, 2009 9:19 pm
ditto tohellandback. I also didn't find any value for X that would make 3^(|x|) < 3^x Only equality holds true.
Hence D
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