BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Permutations and Combinations - doubt

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Sun Feb 11, 2007 2:22 am
by krishnaprasad » Mon Jul 04, 2011 4:28 pm
A committee of 5 is to be selected from among 5 boys and 6 girls. I how many ways can this be done if the committee is to consist of at-least one Girl?
A) 105
B) 225
C) 230
D) 350
E) 455

what is the answer choice and how?
I am still Alive.........
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
GMAT Instructor
Posts: 23
Joined: Thu Jun 09, 2011 11:34 pmFollowed by: 6 members
Location: New York City
Thanked: 17 times

by Jim@Knewton » Mon Jul 04, 2011 6:44 pm
The question appears to be erroneous / incomplete / answer choices are wrong - what is the source of this question?
As is, the answer should be: 461 possible ways to select a com. of 5 with at least 1 g from 5 bs and 6 gs.

BUT if you edit the question to read: "A committee of 5 is to be selected from among 5 boys and 6 girls. In how many ways can this be done if the committee is to consist of at-least one girl and at least one boy?
A) 105 B) 225 C) 230 D) 350 E) 455

Such questions need to be structured in two parts:
1. List the number of possible ways in which the selection (committee) can be composed
Then the possible selection / composition of committee = 1g & 4b (one girl and 4 boys in the committee, and so on), 2g & 3b, 3g & 2b, 4g & 1b

2. Find the number of combination counts possible for each selection.
1g & 4b => 6C1 *5C4 = 6*5 = 30 possible ways (Use combination formula)
2g & 3b => 6C2 *5C3 = 15*10 = 150 possible ways
3g & 2b => 6C3 *5C2 = 20*10 = 200 possible ways
(Note: From a GMAT perspective, you can stop here because the sum of the above 3 = 380 and hence the answer must be E. 455 which is the only value > 380)
4g & 1b => 6C4 * 5C1 = 15*5 = 75 possible ways

Total possible ways = [spoiler]30 + 150 + 200 + 75 = 455[/spoiler]
Hence E.
:-)
Best, Jim
Please "thank" this post if it helps you!
https://www.knewton.com/people/jims
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 613
Joined: Thu Mar 22, 2007 6:17 amFollowed by: 64 members
Location: madrid
Thanked: 171 times
GMAT Score:790

by kevincanspain » Mon Jul 04, 2011 10:17 pm
krishnaprasad wrote:A committee of 5 is to be selected from among 5 boys and 6 girls. I how many ways can this be done if the committee is to consist of at-least one Girl?
A) 105
B) 225
C) 230
D) 350
E) 455

what is the answer choice and how?
Also, you can think as follows: we have to choose 5 from among 11 people. This can done in 11C5=11*10*9*8*7/5! = 462 ways

One of these comittees have 5 boys and 6C5=6 of these comittees have 5 girls
Kevin Armstrong
GMAT Instructor
Gmatclasses
Madrid
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 613
Joined: Thu Mar 22, 2007 6:17 amFollowed by: 64 members
Location: madrid
Thanked: 171 times
GMAT Score:790

by kevincanspain » Mon Jul 04, 2011 10:17 pm
krishnaprasad wrote:A committee of 5 is to be selected from among 5 boys and 6 girls. I how many ways can this be done if the committee is to consist of at-least one Girl?
A) 105
B) 225
C) 230
D) 350
E) 455

what is the answer choice and how?
Also, you can think as follows: we have to choose 5 from among 11 people. This can done in 11C5=11*10*9*8*7/5! = 462 ways

One of these comittees have 5 boys and 6C5=6 of these comittees have 5 girls
Kevin Armstrong
GMAT Instructor
Gmatclasses
Madrid
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1