XY can be even if at least one of the terms is Even
E x E = E
E X O = E
Statement 1)
5x - 4y = E
we can only get even when:
E - E or O - O
E-E
5x = even only when X is even
4y = is even no matter what Y is
0-0
5x = O ; x is ODD
4Y = O ; we have no solution for this
So, both 5x and 4y are EVEN and this statement is Sufficient
Statement 2)
6x+7Y = EVEN
either E+E or O+O
we know that 6X will always be E so
we need to check only
E+E
7Y = EVEN , so Y must be EVEN, so no matter what X is
XY = EVEN
Hence, D
What is OA ?
P.S. Maxx please post the OA with spoiler function
GMAT Numbers
This topic has expert replies
Source: Beat The GMAT — Data Sufficiency |
-
cramya
- Legendary Member
- Posts: 2467
- Joined: Thu Aug 28, 2008 6:14 pm
- Thanked: 331 times
- Followed by:11 members
O - ODD
E- EVEN
RULES:
O*O = O
E*E = E
O*E = E
O+O = E
E+E = E
O-E = O
O-O=E
E-E = E
E-O = O
The product xy will be even if both x and y are even or either one of them is even from rules above
Stmt I
5x-4y is even
5x can be odd and 4y can be odd or 5x can be even and 4y can be even from the rules above for the difference to be even
However 4y cannot be odd since even or odd multiplied by even number 4 is even from the rules above. Therefore 4y is even (y can be odd) but for 5x to be even x has to be even (since 5 is odd if x were odd then odd*odd = odd but we want 5x to be even)
Since we have shown atleast x or y is even the product xy is always even
SUFF
Stmt II
6x+7y - > even
Similar to explanation above -- 6x has to be even (since 6 is even even*anyhting is even) where x xan be odd or even AND also 7y has to even and y has to be even for 7y to be even (since odd*odd will give you odd)
y has to be even therefroe xy is even whether x is even or odd
SUFF
D)
E- EVEN
RULES:
O*O = O
E*E = E
O*E = E
O+O = E
E+E = E
O-E = O
O-O=E
E-E = E
E-O = O
The product xy will be even if both x and y are even or either one of them is even from rules above
Stmt I
5x-4y is even
5x can be odd and 4y can be odd or 5x can be even and 4y can be even from the rules above for the difference to be even
However 4y cannot be odd since even or odd multiplied by even number 4 is even from the rules above. Therefore 4y is even (y can be odd) but for 5x to be even x has to be even (since 5 is odd if x were odd then odd*odd = odd but we want 5x to be even)
Since we have shown atleast x or y is even the product xy is always even
SUFF
Stmt II
6x+7y - > even
Similar to explanation above -- 6x has to be even (since 6 is even even*anyhting is even) where x xan be odd or even AND also 7y has to even and y has to be even for 7y to be even (since odd*odd will give you odd)
y has to be even therefroe xy is even whether x is even or odd
SUFF
D)












