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alltimeacheiver
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value
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pankajks2010
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b cannot be 1. when b becomes 1, the numerator would become 0 and thus, the fraction would result into 0, which would be then different from the RHS.
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Chaitanya_1986
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since given a=1, 1-b/c = 1
-->> 1-b=c
-->> b=1-c
when c=0, b = 1
c=1, b=0
c=2, b=-1
c=3, b=-2
B cannot be 2
-->> 1-b=c
-->> b=1-c
when c=0, b = 1
c=1, b=0
c=2, b=-1
c=3, b=-2
B cannot be 2
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Anurag@Gurome
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What when c = -1?Chaitanya_1986 wrote:since given a=1, 1-b/c = 1
-->> 1-b=c
-->> b=1-c
when c=0, b = 1
c=1, b=0
c=2, b=-1
c=3, b=-2
B cannot be 2
Then, (1-b)/-1 = 1.
Or b = 2.
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niazsna786
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this is a good question .. given is a = b --- (1)
and (a - b)/c = 1 --- (2)
which can be written as (1-b) = c -- (3)
for ever value of c we get a value for b ..
but we should consider the second equation (a-b)/c = 1 is possible only if c is not zero
esle it would become infinity
so value of c should not be zero ..
for value c= 0 in eqn 3 we get b = 1 .. c = 0 is not possible as said above so b cannot have value 1 .
and (a - b)/c = 1 --- (2)
which can be written as (1-b) = c -- (3)
for ever value of c we get a value for b ..
but we should consider the second equation (a-b)/c = 1 is possible only if c is not zero
esle it would become infinity
so value of c should not be zero ..
for value c= 0 in eqn 3 we get b = 1 .. c = 0 is not possible as said above so b cannot have value 1 .
