BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMATPrep Test #2

Expert replies
Source: — Problem Solving |

by jayhawk2001 » Wed Jun 06, 2007 6:46 pm
Problem 1:

If both cold and hot leak together (t), the time taken would be less
than either cold (c) or hot (h).

So, we can form the inequality 0 < t < c < h

We can hence conclude I is true and II is false

If c = h, then t = c/2 = h/2. But we know c < h, so t has to be > c/2 and
less than h/2. So, III is true.

So, E -- I and III only.

-----------------------------------------------------------------------------------------

Problem 2:

(1001+999)(1001-999) / (101+99)(101-99)
= 2000*2 / 200*2
= 10
Join the discussion

by thumpin_termis » Wed Jun 06, 2007 6:57 pm
Love the crystal-clear explanations. Thanks a bunch!
Join the discussion