PR - Geo Question - Need help

This topic has expert replies
Source: — Data Sufficiency |

Master | Next Rank: 500 Posts
Posts: 343
Joined: Mon Jan 21, 2008 3:28 pm
Thanked: 4 times

by arorag » Sat May 10, 2008 12:36 pm
IMO D
From I
first get AB--then r can be found
from II
again area, r can be found

Legendary Member
Posts: 631
Joined: Mon Feb 18, 2008 11:57 pm
Thanked: 29 times
Followed by:3 members

by netigen » Sat May 10, 2008 12:41 pm
In (B) I don't understand how can you find r by just knowing the area of the triangle. All we know is:

1. Triangle is isosceles with two sides = r
2. Area of the triangle

User avatar
GMAT Instructor
Posts: 189
Joined: Thu May 01, 2008 10:55 pm
Location: Seattle, WA
Thanked: 25 times
Followed by:1 members
GMAT Score:750+

by VP_Tatiana » Sat May 10, 2008 6:09 pm
Here is how you get r by knowing AD:

Draw a line from A to O. Now we have triangle AOD.

We know AO is r, OD is (r-2), and AD is 6.

You can see we could solve for r using the Pythagorean theorum. Thus, knowing AD is sufficient to solve for r.

Of course, now we could solve for circumference because it is 2pir.

Hope that helped,

Tatiana
Tatiana Becker | GMAT Instructor | Veritas Prep

Legendary Member
Posts: 631
Joined: Mon Feb 18, 2008 11:57 pm
Thanked: 29 times
Followed by:3 members

by netigen » Sat May 10, 2008 8:23 pm
Tatiana, that solves for A, how about the option B? In your opinion, is B sufficient to solve for r? If yes, then how?
VP_Tatiana wrote:Here is how you get r by knowing AD:

Draw a line from A to O. Now we have triangle AOD.

We know AO is r, OD is (r-2), and AD is 6.

You can see we could solve for r using the Pythagorean theorum. Thus, knowing AD is sufficient to solve for r.

Of course, now we could solve for circumference because it is 2pir.

Hope that helped,

Tatiana

Master | Next Rank: 500 Posts
Posts: 294
Joined: Tue Feb 26, 2008 9:05 pm
Thanked: 13 times
Followed by:1 members

by amitansu » Sun May 11, 2008 9:46 am
From 2:

Area of triangle 1/2 *base*alt=50

here base=alt=radius of traingle


so 1/2r^2=50
r=10

Legendary Member
Posts: 631
Joined: Mon Feb 18, 2008 11:57 pm
Thanked: 29 times
Followed by:3 members

by netigen » Sun May 11, 2008 12:35 pm
You are assuming the triangle is a right angle triangle. The question doesn't say that its a right angle triangle. This is of course my read on the question and I may be wrong hence need to understand why everyone is interpreting the triangle to be right angled.
amitansu wrote:From 2:

Area of triangle 1/2 *base*alt=50

here base=alt=radius of traingle


so 1/2r^2=50
r=10

User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 am
Location: India
Thanked: 51 times
Followed by:1 members

by gabriel » Sun May 11, 2008 1:37 pm
amitansu wrote:From 2:

Area of triangle 1/2 *base*alt=50

here base=alt=radius of traingle


so 1/2r^2=50
r=10
I am confused, how exactly did you reach the conclusion that base = alt=radius. This would be true only if OBC is a isosceles right angle triangle. The question gives no indication of this. I believe the answer should be A, the solution for which is already provided.

Legendary Member
Posts: 631
Joined: Mon Feb 18, 2008 11:57 pm
Thanked: 29 times
Followed by:3 members

by netigen » Sun May 11, 2008 3:08 pm
BTW the OA by PR for this is D. Explanation assumes the tirangle to the right angled. Anyone know how to give feedback to PR about this error.
Attachments
Untitled 1.jpg

Senior | Next Rank: 100 Posts
Posts: 73
Joined: Fri Feb 01, 2008 1:28 am
Location: India
Thanked: 1 times
Followed by:1 members

by sandeep_chhabra » Mon May 12, 2008 12:03 am
Cant we use the formula for Isosceles Triangle ??

Image

Master | Next Rank: 500 Posts
Posts: 294
Joined: Tue Feb 26, 2008 9:05 pm
Thanked: 13 times
Followed by:1 members

by amitansu » Mon May 12, 2008 12:56 am
Yes, there could be a misprint in book.Right angle has to be assumed here.But not necessarily isoseceles triangle !!

Because, for triangle OBC it shows the two sides are nothing but radii.

So the formula can be reduced to 1/2 alt*base=50
=> 1/2*r*r=50

Legendary Member
Posts: 631
Joined: Mon Feb 18, 2008 11:57 pm
Thanked: 29 times
Followed by:3 members

by netigen » Mon May 12, 2008 1:10 am
Sandeep, the formula you have posted can not be used because one variable in the formula is the base of the triangle and the other is one of the equal sides.

Amit, I also think this is an error on part of PR. This problem is from one of their tests and not from the book.