a, b, c, d, and e are five numbers such that a≤b≤c≤d≤e and e-c=4. A is the average (arithmetic mean) of the five numbers, and M is their median. Is A>M?
(1) e+c=3
(2) c=a+10
(1) e+c=3
(2) c=a+10
my approach:
I look at deviation. For A= M the deviation must zero out
I set the middle term (C) = 0; Since e-a=14 and e-c=4. e is 4 higher than c and a is less than c. Thus:
-10,b,0,d,+4. The left side has the min deficit of -10 if b=c. The the highest b can be is +4. So there's no way to make it balance. Thus average has to be less than median.
Please give me feedback on my approach. Is this correct?
