You just made things much easier for me. This is EXACTLY how I am wired and I fully understand now! I can do the other ways but this way is crystal clear and I can back it up and even teach others how to do it this way. The moral or takeaway that I am learning is that you have to account for the EXTRA part and try to make the two things equal. THen the computations are fairly straightforward. I had a similiar problem and it looked like this:
Train A left centerville , heading toward dale city station, at 3pm. Train b left dale heading toward centerville at 3:20 on the same day. The trains rode on straight tracks that were parallel to each other. If train a traveled at 30 mph and train b at 10 mph and the distance between stations were 90 miles, when did the trains pass eachother?
a. 4:45
b. 5:00
c. 5:20
d.5:35
e.6:00
qa
is c
and your easy solution was great. How can I learn more of ways to approach this in the rey.fernandez way.
Appetite for 700 and I scraped my plate!
