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Gmat practice test problem

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by vladmire » Tue Oct 14, 2008 5:57 pm
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

None
Q Only
Q and R
P, Q and R
P, Q, R and S

R is a square and I cant figure out how they get 2 as the area when the legnth of the side is 2.
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by Gmatss » Tue Oct 14, 2008 6:01 pm
it will be nice if you provide the picture to look at...
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by vladmire » Tue Oct 14, 2008 6:03 pm
How do I copy the picture. Its on the the Gmat Practice Test 1 from MBA.com
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by stop@800 » Wed Oct 15, 2008 12:24 am
use print screen button and paste in mspaint.
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Oh yea

by vladmire » Wed Oct 15, 2008 4:21 pm
thks
Image

Here is the problem

my question is how is the square 2 its 2^2 right = 4
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by bekkilyn » Wed Oct 15, 2008 4:44 pm
Think of R as two triangles put together rather than a square. Since the area of a triangle is (1/2)bh, the two triangles would be (1/2)(2)(1) + (1/2)(2)(1) = 2.

You can't just do base x height for a square using length 2 since the sides of the square are not 2 (or 1 depending on how you are looking at it on the graph), but sqrt(2), using the pythagorean theorem for a triangle (dividing the shape into 4 right triangles).

So base x height for the square would be (sqrt(2))(sqrt(2)) = 2
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Re: Oh yea

by Gmatss » Wed Oct 15, 2008 5:15 pm
vladmire wrote:thks
Image

Here is the problem

my question is how is the square 2 its 2^2 right = 4
For R u have to Cut the square down the middle and take it as two triangles. theirs sides are not 2 since the square is not rightside up.
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Thks

by vladmire » Wed Oct 15, 2008 6:02 pm
Ok I was thinking I could flip the square right side up
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by rohangupta83 » Thu Oct 16, 2008 12:45 am
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identify that for square R each side is sqrt 2. Then just multiply the sides sqrt2 X sqrt2 = 2
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