voodoo_child wrote:If A, B, C and D form a quadrilateral.
Is AC > BD ?
a) Angle ABC < Angle BCD
b) AB = BC= CD = DA
I was to able to figure out that b) is insufficient. Any thoughts about a) ?
OA - c
thanks
Voodoo
Statement 1: ∠ABC < ∠BCD.
∠ABC < ∠BCD and AC<BD:
∠ABC < ∠BCD and AC>BD:
Insufficient.
Statement 2: AB=BC=CD=DA.
If ABCD is a square, then AC=BD.
If ABCD is a rhombus that is not a square, then one diagonal is longer than the other. No way to determine whether AC>BD or AC<BD.
Insufficient.
Statement 1 and 2 together: ∠ABC < ∠BCD and AB=BC=CD=DA.
Since all the sides are equal and ∠ABC < ∠BCD, we know that AC<BD:
The correct answer is
C.
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