For which of the following values of x is (1-((2-((x)^1/2))^1/2))^1/2 not defined as the real number.
Answers:
1
2
3
4
5
to answer this question you shd knw the definition of real number...
If the number doesnt exist or its an imaginary number then its not a real number
such as (-3)^1/2
subst x =5 (squr root of 5 is >2)
(2-(2.23))^1/2 which doesnt exist
you can try other choices tooo
I will go with 5
real number problem
This topic has expert replies
Source: Beat The GMAT — Problem Solving |
-
kabirmohammed
- Junior | Next Rank: 30 Posts
- Posts: 15
- Joined: Mon Nov 23, 2009 6:23 pm
- Thanked: 1 times
nailyad,
I understand your logic for number 5... the square root of any negative number is imaginary. My question is, how would you remove 4 as a possiblity? With x as 4, you would get:
a) sqrt(1-(sqrt(2- 2))
OR
b) sqrt(1-(sqrt(2- (-2)) (Remeber that a square root can be the positive or negative)
In scenario a, the answer from there would end up being sqrt(1-0)... which would just equal 1.
In scenario b, the answer would be sqrt(1-(sqrt4)) = sqrt(1-2) = sqrt(-1)... Also NOT a real number!!!! Does anyone else see this, or am I doing something wrong here?
NOTE: I haven't done the math, but I believe the same would hold true for 2 and 3...
I understand your logic for number 5... the square root of any negative number is imaginary. My question is, how would you remove 4 as a possiblity? With x as 4, you would get:
a) sqrt(1-(sqrt(2- 2))
OR
b) sqrt(1-(sqrt(2- (-2)) (Remeber that a square root can be the positive or negative)
In scenario a, the answer from there would end up being sqrt(1-0)... which would just equal 1.
In scenario b, the answer would be sqrt(1-(sqrt4)) = sqrt(1-2) = sqrt(-1)... Also NOT a real number!!!! Does anyone else see this, or am I doing something wrong here?
NOTE: I haven't done the math, but I believe the same would hold true for 2 and 3...

















