dapplegate wrote:HOW DOES?
X^2-5X-X=0 become (X-6)(X+1)=0
AND
n^2-14n+49=0 become (n-7)(n-7)=0
AND
(X-2)^2 become X^2 -4X +4
these are simple question of factorization and you have to solve some of these problems to actually master these type of problems.
ok going with first question
X^2-5X-6=0 so here first check for for -6(which is constant term and factorize is so we get -6 = -1 x 2 x 3 x1
so we start making combination of factors in two such that their sum = middle term
here we find -6 x 1= -6(constant term) and -6 +1 = -5 (coeff. of x)
so we try to arrange the given terms that way X^2-5X-6=0 --> X^2-6X + X-6=0 --> X(X-6) + 1(X-6) =0 --> (X-6) (X+1) =0
2nd question
n^2-14n+49=0
again the same process
n^2-14n+49=0 --> n^2-7n-7n 49=0 --> (n-7) (n-7)=0
rather u can solve it by a simple formulae
(a-b)^2 = (a-b)(a-b) = (a^2- 2ab - b^2)
3rd question
again use the same formulae for this question and you will get the result
(X-2)^2= X^2 -4X +4
