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Source: — Data Sufficiency |

by Matt@VeritasPrep » Sun Mar 22, 2015 10:02 pm
Let's start by simplifying the exponents.

2ˣ = 4ʸ = 8ᶻ

is really

2ˣ = (2²)ʸ = (2³)ᶻ

so

x = 2y = 3z

we also have

xyz = 288

Now just do substitution. Since x = 2y and z = (2/3)y, we have

xyz = 2y*y*(2/3)y = 288

That gives y = 6

From this, x = 12 and z = 4.

The sum at the end is 1/24 + 1/24 + 1/32, or 11/96.
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by sandipgumtya » Sun Mar 22, 2015 11:12 pm
Thanks for quick repl.Is this GMAT relevant?
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by GMATGuruNY » Mon Mar 23, 2015 3:39 am
The problem should read as follows:
If 2ˣ = 4ʸ = 8ᶻ and xyz=288, what is the value of 1/(2x) + 1/(4y) + 1/(8z)?

A) 18/74
B) 18/96
C) 11/74
D) 11/96
Let 2ˣ = 4ʸ = 8ᶻ = 64.
In this case, x=6, y=3 and z=2.
Implication:
x:y:z = 6:3:2.

Test multiples of this ratio until a product of 288 is yielded:
6*3*2 = 36.
12*6*4 = 288.
The option in red works.

Since x=12, y=6, and z=4, we get:
1/(2x) + 1/(4y) + 1/(8z) = 1/24 + 1/24 + 1/32 = 4/96 + 4/96 + 3/96 = 11/96.

The correct answer is D.
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