(1) r = 3s = 2t = 6ugrandh01 wrote:If x = 0. rstu, where r, s, t, and u
each represent a nonzero digit of x,
what is the value of x?
(1) r = 3s = 2t = 6u
(2) The product of r and u is equal to
the product of s and t.
Since r, s, t and u are a nonzero digit so for r, which is equal to 6u, to be a nonzero digit u must be 1 (because if u is 2 or more than 2, then r will not be a digit, and u also can not be zero as given that all unknowns are nonzero).
This implies r = 6, s = 2, t = 3, and u = 1
So, x = 0.6231; SUFFICIENT.
(2) The product of r and u is equal to the product of s and t implies multiple values of x are possible: x = 0.1111, x = 2222, x = 1221, ...
No definite answer; NOT sufficient.
The correct answer is A.
