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That's a good question.ankur.agrawal wrote:Peter, Paul, and Mary each received a passing score on his/her history midterm. The average (arithmetic mean) of the three scores was 78. What was the median of the three scores?
(1) Peter scored a 73 on his exam.
(2) Mary scored a 78 on her exam.
Oa after some discussion.
@smackmartine: Just a thought here what if all scored 78? it's not necessary that if M=78 then one scored above 78 and other less than 78.smackmartine wrote:IMO B
Total scores (Pe+Pa+M )=78*3=234
1)Pe = 73 so Pa+M= 234-73 = 161
161 does not clarify individual scores of both Paul and Mary.
if Pa = 74 => M =161-74 = 87 (in this case median is 74 )
also if Pa= 72 ,M = 161- 72= 89 (in this case medial is 73)
so 1 is Insufficient
2) if M= 78
In order for average to be 78 one of the score should be less than 78 and other should be greater than 78 with the same difference . eg is if one is 75 then other should be 81 so median in any case is 78
So statement 2 is Sufficient.
So B
M09 wrote:ohh.. Sorry B ..typing mistakesmackmartine wrote:IMO B
Total scores (Pe+Pa+M )=78*3=234
1)Pe = 73 so Pa+M= 234-73 = 161
161 does not clarify individual scores of both Paul and Mary.
if Pa = 74 => M =161-74 = 87 (in this case median is 74 )
also if Pa= 72 ,M = 161- 72= 89 (in this case medial is 73)
so 1 is Insufficient
2) if M= 78
In order for average to be 78 one of the score should be less than 78 and other should be greater than 78 with the same difference . eg is if one is 75 then other should be 81 so median in any case is 78
So statement 2 is Sufficient.
So B
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