Pls chk if approach is correct?

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by jimmiejaz » Tue Nov 04, 2008 3:58 pm
Stacey Koprince wrote:Received a PM asking me to respond. From the top:

Question stem:
n is not zero, so either pos or neg. could be non-integer.
yes/no question
In order for abs. value of n to be < 4, n would have to be between -4 and 4. So I can rephrase:
is -4 < n < 4? (and n is not zero)

(1)
I'll assume "n2" means n^2. Please correct me if that's wrong.
n^2 > 16
n > +4 and n < -4
definitive no. Sufficient. Eliminate B, C, E.

(2)
1/|n| > n
You're testing this as though you have to flip the sign when you multiply things by n, but you don't. n is inside an absolute value sign, and you are multiplying by everything (including the absolute value sign), which means that it's definitely positive (or it could be zero in a different problem, but not in this one, since n does not equal zero).

So you can just say 1 > n * |n| because what you're multiplying by is definitely a positive value. Don't do what a lot of you did next, though, and rewrite this as 1 > n^2. That's not equivalent!

Try some numbers above to understand what that inequality means. If n = -2, then n * |n| = -4. -4 < 1, so this fulfills statement 2. We're allowed to choose n = -2. In this case, n is between -4 and 4, so if n = -2, then the answer to the question is yes.

Now try something else and specifically see whether you can get a "no" answer (since you already have a yes). This requires us to pick something either smaller than -4 or larger than 4. What about n = -10? Then n * |n| = -100 and -100 < 1, so this also fulfills statement 2 and we're allowed to choose n = -10. This time, the answer to the question is no.

Essentially, if we use any negative number at all for n, we'll make the statement true (because if you multiply n by the absolute value of n, you will multiple one negative and one positive number; the result of that is always negative). But some negative numbers will give us a "yes" answer and some will give us a "no" answer.

Insufficient. Answer is A.

(Notice also that the statements do not contradict, as some said above. Statements should never contradict each other.)
thanks a lot Stacey for your explanation. That cleared all the doubts. Now i know whr my reasoning was wrong. Even while i solved it which i shouldnt have, i mistakenly took the range of both the scenarios and added them, which i can't do. i got n>-1 and n<1 and i made it
-1<n<1 which is wrong.
Anyways thanks for your approach. I will keep this in mind now.

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just great

by simba12123 » Tue Nov 04, 2008 7:29 pm
Stacy,

Thank you so much. I am learning to keep things as simple as possible. :)
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by lunarpower » Fri Nov 14, 2008 5:05 am
stacey for the win. a couple of extra comments, though:

first of all, here's a really important fact that you should know about absolute values and squares.
FACT: &#8730;(expression^2) = |expression|

you should know this. in words: if you square a quantity, and then take the square root of the resulting square, then you get the absolute value of the original expression.
this happens because squaring makes the quantity "go positive", and, once that happens, the quantity will still be positive once you have taken its square root.

therefore, since both sides of statement #1 are positive, you can take the square root of both sides:
n^2 > 16
&#8730;(n^2) > &#8730;16
|n| > 4
this is sufficient.

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statement (2): your FIRST INSTINCT, for statements like this one, should be to TEST POSITIVES AND NEGATIVES.
in other words, you should test number properties (for positive and negative numbers) on statements like this one BEFORE you treat them as bona fide inequalities.
if you do so, you'll quickly realize that this statement is true for all negative numbers, as pointed out by stacey above. that realization proves that #2 is insufficient, as there are negative numbers whose absolute values are greater than 4 as well as negative numbers whose absolute values are less than 4.
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by maihuna » Wed Apr 15, 2009 10:19 am
Hi Ian,

My doubt here is with following eqn:

n^2 > -1

How to interpret it logically? I dont want to pick a no and come to contradiction but some methods to find contradiction.

The two scenario here are: n^2<1 n^2>-1

Now what?
for n^2<1 is |n|<1 or -1<n<1

what should i do for n^2>-1??

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by Ian Stewart » Wed Apr 15, 2009 12:55 pm
maihuna wrote: what should i do for n^2>-1??
Very often, the first questions I'll ask myself when looking at a simple inequality are the following: is the left side positive or negative? Is the right side positive or negative? If you see:

n^2 > -1

then the right side is clearly negative. The left side is either positive or zero. So the inequality is always true, and the inequality doesn't tell you anything about n. Alternatively, you could add 1 to both sides:

n^2 + 1 > 0

And since the left side is 1 or larger, the inequality is always true.
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