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by kmittal82 » Fri Jul 09, 2010 7:42 am
2^x/2^y = 2^(x-y)

You need to work the value in the () first:

(3@1) = 2^(3-1) = 2^2 = 4
4 @ 3 = 2^(4-3) = 2
Answer is A
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by amising6 » Fri Jul 09, 2010 7:45 am
monteleone82 wrote:Please help with this question from GMAT Prep.


If the operation @ is defined for all positive integers x and w by x @ w = 2^x/2^w, then (3 @ 1) @ 3 =

A. 2
B. 4
C. 8
D. 16
E. 32
x @ w = 2^x/2^w = 2^(x-y)
(3 @ 1) @ 3= (2^(3-1)) @3
=2^2@3
=4@3
=2^(4-3)
=2
Ideation without execution is delusion
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