j_shreyans wrote:Hi ,
Small doubt in the below question .
Statement 1 says b=160a/100 or 8a/5
so can we put b in the ab/40 then find out the remainder, doing this will get a^2/25 and a is positive integers so by this statement 1 is not sufficient.
Please advise and correct me .
Thanks
Since b = (8/5)a -- and b is an integer -- a must be a multiple of 5, as in the following cases:
a=5, b = (8/5)(5) = 8.
a=10, b = (8/5)(10) = 16.
a=15, b = (8/5)(15) = 24.
And so on.
Since a is a multiple of 5, a² must be a multiple of 25, implying that dividing a² by 25 will leave a remainder of 0.
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