Statement 1: The mean of set S is an even number.
For a set of consecutive even numbers, if the number of elements in the set is even, the mean will be the average of the two middle elements, and will always be an odd number. Consider the following set.
{2, 4, 6, 8} The sum of the elements is 20, and the mean is 5.
The median will also be the average of the two middle elements, 4, and 6, which is 5. So the median of such a set will also be odd.
If the number of elements in the set is odd, the mean will always equal the value of the middle element of the set. Consider the following set.
{2, 4, 6, 8, 10}
The mean is 6.
The median is also, 6, which is even.
So if the mean of a set of consecutive even numbers is even, the median is even.
Sufficient.
Statement 2: The range of set S is divisible by 4.
The range is the difference between the highest value and the lowest value in the set.
Consider a set with range 8, which is divisible by 4. {2, 4, 6, 8, 10}
Notice that when 8 is divided by 4, we get 2. So we could say that there are four 2's in 8.
However, set {2, 4, 6, 8}, which has an even number of elements, has a range of only 8 - 2 = 6. To have a range of 8, the set needs an additional element, 10, the addition of which makes the number of elements odd.
It will always be the case that in order for the range of a set of consecutive even numbers to be divisible by 4, the set will have to have that additional element that makes the number of elements odd.
A set made up of an odd number of consecutive even numbers always has an even median, as illustrated in the discussion of Statement 1.
Sufficient.
The correct answer is D.