The following is a question from the the GMAT Official Review 13th edition. I am not in agreement with the answer provided by the book. Please help explain.
A closed cylindrical tank contains 36Ï€ cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is 2 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
My solution: 36Ï€ = (Ï€r^2xh)/2 ; h being the full hight of the cylinder and r being the radius of the base.
The book's solution: 36π = πr^2xh
If 36Ï€ represents the water volume which represents only half of the volume of the cylinder, how can the book be right?
Can someone please help on this one?
Thanks,
Dalia
A closed cylindrical tank contains 36Ï€ cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is 2 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
My solution: 36Ï€ = (Ï€r^2xh)/2 ; h being the full hight of the cylinder and r being the radius of the base.
The book's solution: 36π = πr^2xh
If 36Ï€ represents the water volume which represents only half of the volume of the cylinder, how can the book be right?
Can someone please help on this one?
Thanks,
Dalia












