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by sanju09 » Tue Nov 10, 2009 1:34 am
The arithmetic mean of the 5 consecutive integers starting with 's' is 'a'. What is the arithmetic mean of 9 consecutive integers that start with s + 2?
A. 2 + s + a
B. 2 + a
C. 2 s
D. 2 a + 2
E. 4 + a
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by vivek.kapoor83 » Tue Nov 10, 2009 2:27 am
5 consecutive no. will be
s,s+1,s+2,s+3,s+4
adding 5 nos and dividin by 5
(5s+10)/5 = a
s = a-2 .........eq(1)

now, s+2...9 consective integers
adding all 9 will give : 9s+54
AM = (9s+54)/9
AM = s+6
put s = a-2 from eq (1)

AM = a-2+6
AM = a+4
Hence E.
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by gmatv09 » Tue Nov 10, 2009 2:54 pm
another approach ...

since we know that the no. of integers in the set is odd..
the avg = middle term
so, s+2 = a or s = a-2

similarly, s+6 = avg of 9 integers
==> a-2+6 = a+4 (E)
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