BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

500 PS # 15

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 269
Joined: Sun Apr 01, 2007 5:41 am
by dunkin77 » Sun Apr 01, 2007 6:07 am
Hi,

The answer is B) but I would like to get explanation - can anyone help?


n= 2*3*5*7*11*13 / 77K

If n is an integer and then which of the following could be the value of k?
(A) 22
(B) 26
(C) 35
(D) 54
(E) 60
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pmFollowed by: 2 members
Location: Arabian Sea
Thanked: 125 times

Re: 500 PS # 15

by ajith » Sun Apr 01, 2007 6:58 am
dunkin77 wrote:Hi,

The answer is B) but I would like to get explanation - can anyone help?


n= 2*3*5*7*11*13 / 77K

If n is an integer and then which of the following could be the value of k?
(A) 22
(B) 26
(C) 35
(D) 54
(E) 60
n= 2*3*5*7*11*13 / 77K
= 2*3*5*7*11*13/ (11*7)K
= 2*3*5*13/k

For this to be an integer K should be a multiple of 2,3,5,13 or a combination of these

22 = 11*2 -Violates the condition
26 = 2*13 (perfect!)
35 = 7 * 5- Violates the condition
54 = 3*3*3*2 -- Violates the condition
60 = 3*2*2*5 - Violates the condition
Always borrow money from a pessimist, he doesn't expect to be paid back.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 269
Joined: Sun Apr 01, 2007 5:41 am

by dunkin77 » Sun Apr 01, 2007 9:02 am
Thanks,

Yes, I figured since, 11*7 is already included in 77K, K must be the combination of 2,3,5,13. So, the combnation dose not necesarily include all of them but just need to include part of them without including other numbers, corrrect?

Thanks again! :D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pmFollowed by: 2 members
Location: Arabian Sea
Thanked: 125 times

by ajith » Sun Apr 01, 2007 9:18 am
dunkin77 wrote:Thanks,

Yes, I figured since, 11*7 is already included in 77K, K must be the combination of 2,3,5,13. So, the combnation dose not necesarily include all of them but just need to include part of them without including other numbers, corrrect?

Thanks again! :D
You are right

K must be the combination of 2,3,5,13 and when you factorize K it should contain these numbers (2,3,5,13) only once.
It can be part or full , no problem!
Always borrow money from a pessimist, he doesn't expect to be paid back.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 2469
Joined: Thu Apr 20, 2006 12:09 pmFollowed by: 14 members
Location: BtG Underground
Thanked: 85 times

by aim-wsc » Sun Apr 01, 2007 9:55 am
wow! Alith is back 8)
go to intro section and tell us how have you been? :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 559
Joined: Tue Mar 27, 2007 1:29 amFollowed by: 2 members
Thanked: 5 times

by Cybermusings » Mon Apr 02, 2007 5:14 am
77 is a product of 7 and 11 so now you have the equation 2*3*11*13 / k left for you

For 2*3*11*13 / k to be an integer it is important that the product of two or more of the set (2,3,11, 13) be completely divisible by k. Now look at Choice B i.e. 26 ;
26 = 13*2 ; Hence it's possible for k = 26

This is not possible for any other number
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 1462
Joined: Thu Apr 09, 2015 9:34 amFollowed by: 22 members
Location: New York, NY
Thanked: 39 times

by Jeff@TargetTestPrep » Sun Jun 24, 2018 5:01 pm


n= 2*3*5*7*11*13 / 77K

If n is an integer and then which of the following could be the value of k?
(A) 22
(B) 26
(C) 35
(D) 54
(E) 60
Since 77 = 7 x 11, we see that k can be 2 x 3 x 5 x 13, or any factor of 2 x 3 x 5 x 13. Since 26 = 2 x 13, B is the correct answer.

Answer: B

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1