-
coolgirl26
- Senior | Next Rank: 100 Posts
- Posts: 71
- Joined: Tue Mar 03, 2009 1:24 pm
Just plug in the values. Parenthesis first, so 3 o 1 = 2^3 / 2^1 = 2^2 = 4.
Now 4 o 3 = 2^4 / 2^3 = 2^1 = 2.
Remember, (x^n) / (x^m) = x^(n-m). This is a very useful identity, and comes into play on several questions on any given test. Similarly, x^n * x^m = x^(n+m).
