BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

solved correctly

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760
by sanju09 » Sat Feb 13, 2010 1:12 am
A GMAT's quant question is given to 3 students who have 1/3, ¼ and ½ chances of solving it correctly. What are the chances that the problem will be solved correctly?
(A) ¼
(B) 1/3
(C) 2/3
(D) ¾
(E) 31/40
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
MBA Student
Posts: 403
Joined: Tue Dec 22, 2009 7:32 pmFollowed by: 22 members
Thanked: 98 times

by fibbonnaci » Sat Feb 13, 2010 1:36 am
the question in essence asks us to find the probability of atleast one solving the question correctly.

atleast questions are best answered using the formula:

1- none of them solve the question.

for none to solve the question:it is the prob of 1st person not solving * 2nd person not solving *3rd person not solving.

probability of 1st person not solving = 2/3
2nd person not solving= 3/4
3rd person not solving = 1/2

2/3*3/4*1/2 =>1/4.

1-1/4 => 3/4 => D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pmFollowed by: 2 members
Location: Arabian Sea
Thanked: 125 times

by ajith » Sat Feb 13, 2010 7:07 am
sanju09 wrote:A GMAT's quant question is given to 3 students who have 1/3, ¼ and ½ chances of solving it correctly. What are the chances that the problem will be solved correctly?
(A) ¼
(B) 1/3
(C) 2/3
(D) ¾
(E) 31/40
The probability that each of them solve it wrong = 2/3 , 3/4 and 1/2
Since these are independent events chances of these happening together = 2/3*3/4*1/2 = 1/4

Since the probability that all of them getting it wrong is 1/4, probability that any of them getting it correct is 1-1/4 = 3/4
Always borrow money from a pessimist, he doesn't expect to be paid back.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1