exponents

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by kvcpk » Fri Jul 16, 2010 1:12 pm
amirp wrote:what is d^6 / d^8

is it

1 / d^(-2)

or

1 / d^2?
1 / d^2 = d^(-2)

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by shashank.ism » Sat Jul 17, 2010 3:18 am
amirp why are u confused in this question...
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by selfmade » Sat Jul 17, 2010 10:51 am
answer is 1/d^2

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d^6/d^8 = d^(6-8) = d^ (-2)=1/d^2